3(y-4)=-2(y+4)

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Solution for 3(y-4)=-2(y+4) equation:



3(y-4)=-2(y+4)
We move all terms to the left:
3(y-4)-(-2(y+4))=0
We multiply parentheses
3y-(-2(y+4))-12=0
We calculate terms in parentheses: -(-2(y+4)), so:
-2(y+4)
We multiply parentheses
-2y-8
Back to the equation:
-(-2y-8)
We get rid of parentheses
3y+2y+8-12=0
We add all the numbers together, and all the variables
5y-4=0
We move all terms containing y to the left, all other terms to the right
5y=4
y=4/5
y=4/5

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