3(y-4)=-2y-12=

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Solution for 3(y-4)=-2y-12= equation: 



3(y-4)=-2y-12=

We move all terms to the left:

3(y-4)-(-2y-12)=0

We multiply parentheses

3y-(-2y-12)-12=0

We get rid of parentheses

3y+2y+12-12=0

We add all the numbers together, and all the variables

5y=0

y=0/5

y=0

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