3(y-4)=-3y+24

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Solution for 3(y-4)=-3y+24 equation: 



3(y-4)=-3y+24

We move all terms to the left:

3(y-4)-(-3y+24)=0

We multiply parentheses

3y-(-3y+24)-12=0

We get rid of parentheses

3y+3y-24-12=0

We add all the numbers together, and all the variables

6y-36=0

We move all terms containing y to the left, all other terms to the right

6y=36

y=36/6

y=6

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