3(y-4)=-y-12

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Solution for 3(y-4)=-y-12 equation: 



3(y-4)=-y-12

We move all terms to the left:

3(y-4)-(-y-12)=0

We add all the numbers together, and all the variables

3(y-4)-(-1y-12)=0

We multiply parentheses

3y-(-1y-12)-12=0

We get rid of parentheses

3y+1y+12-12=0

We add all the numbers together, and all the variables

4y=0

y=0/4

y=0

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