3(y-4)=11y-y

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Solution for 3(y-4)=11y-y equation: 



3(y-4)=11y-y

We move all terms to the left:

3(y-4)-(11y-y)=0

We add all the numbers together, and all the variables

3(y-4)-(+10y)=0

We multiply parentheses

3y-(+10y)-12=0

We get rid of parentheses

3y-10y-12=0

We add all the numbers together, and all the variables

-7y-12=0

We move all terms containing y to the left, all other terms to the right

-7y=12

y=12/-7

y=-1+5/7

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