3(y-4)=2(y-2)

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Solution for 3(y-4)=2(y-2) equation:


Simplifying
3(y + -4) = 2(y + -2)

Reorder the terms:
3(-4 + y) = 2(y + -2)
(-4 * 3 + y * 3) = 2(y + -2)
(-12 + 3y) = 2(y + -2)

Reorder the terms:
-12 + 3y = 2(-2 + y)
-12 + 3y = (-2 * 2 + y * 2)
-12 + 3y = (-4 + 2y)

Solving
-12 + 3y = -4 + 2y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-2y' to each side of the equation.
-12 + 3y + -2y = -4 + 2y + -2y

Combine like terms: 3y + -2y = 1y
-12 + 1y = -4 + 2y + -2y

Combine like terms: 2y + -2y = 0
-12 + 1y = -4 + 0
-12 + 1y = -4

Add '12' to each side of the equation.
-12 + 12 + 1y = -4 + 12

Combine like terms: -12 + 12 = 0
0 + 1y = -4 + 12
1y = -4 + 12

Combine like terms: -4 + 12 = 8
1y = 8

Divide each side by '1'.
y = 8

Simplifying
y = 8

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