3(y-4)=24+4y

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Solution for 3(y-4)=24+4y equation: 



3(y-4)=24+4y

We move all terms to the left:

3(y-4)-(24+4y)=0

We add all the numbers together, and all the variables

3(y-4)-(4y+24)=0

We multiply parentheses

3y-(4y+24)-12=0

We get rid of parentheses

3y-4y-24-12=0

We add all the numbers together, and all the variables

-1y-36=0

We move all terms containing y to the left, all other terms to the right

-y=36

y=36/-1

y=-36

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