3(y-4)=3(2y+1)

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Solution for 3(y-4)=3(2y+1) equation:



3(y-4)=3(2y+1)
We move all terms to the left:
3(y-4)-(3(2y+1))=0
We multiply parentheses
3y-(3(2y+1))-12=0
We calculate terms in parentheses: -(3(2y+1)), so:
3(2y+1)
We multiply parentheses
6y+3
Back to the equation:
-(6y+3)
We get rid of parentheses
3y-6y-3-12=0
We add all the numbers together, and all the variables
-3y-15=0
We move all terms containing y to the left, all other terms to the right
-3y=15
y=15/-3
y=-5

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