3(y-4)=5(2y-1)

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Solution for 3(y-4)=5(2y-1) equation: 



3(y-4)=5(2y-1)

We move all terms to the left:

3(y-4)-(5(2y-1))=0

We multiply parentheses

3y-(5(2y-1))-12=0



We calculate terms in parentheses: -(5(2y-1)), so:

5(2y-1)

We multiply parentheses

10y-5

Back to the equation:

-(10y-5)



We get rid of parentheses

3y-10y+5-12=0

We add all the numbers together, and all the variables

-7y-7=0

We move all terms containing y to the left, all other terms to the right

-7y=7

y=7/-7

y=-1

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