3(y-4)=5(y+2)

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Solution for 3(y-4)=5(y+2) equation: 



3(y-4)=5(y+2)

We move all terms to the left:

3(y-4)-(5(y+2))=0

We multiply parentheses

3y-(5(y+2))-12=0



We calculate terms in parentheses: -(5(y+2)), so:

5(y+2)

We multiply parentheses

5y+10

Back to the equation:

-(5y+10)



We get rid of parentheses

3y-5y-10-12=0

We add all the numbers together, and all the variables

-2y-22=0

We move all terms containing y to the left, all other terms to the right

-2y=22

y=22/-2

y=-11

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