3(y-4)=5(y+2)-y

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Solution for 3(y-4)=5(y+2)-y equation:


Simplifying
3(y + -4) = 5(y + 2) + -1y

Reorder the terms:
3(-4 + y) = 5(y + 2) + -1y
(-4 * 3 + y * 3) = 5(y + 2) + -1y
(-12 + 3y) = 5(y + 2) + -1y

Reorder the terms:
-12 + 3y = 5(2 + y) + -1y
-12 + 3y = (2 * 5 + y * 5) + -1y
-12 + 3y = (10 + 5y) + -1y

Combine like terms: 5y + -1y = 4y
-12 + 3y = 10 + 4y

Solving
-12 + 3y = 10 + 4y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-4y' to each side of the equation.
-12 + 3y + -4y = 10 + 4y + -4y

Combine like terms: 3y + -4y = -1y
-12 + -1y = 10 + 4y + -4y

Combine like terms: 4y + -4y = 0
-12 + -1y = 10 + 0
-12 + -1y = 10

Add '12' to each side of the equation.
-12 + 12 + -1y = 10 + 12

Combine like terms: -12 + 12 = 0
0 + -1y = 10 + 12
-1y = 10 + 12

Combine like terms: 10 + 12 = 22
-1y = 22

Divide each side by '-1'.
y = -22

Simplifying
y = -22

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