3(y-4)=6y+6

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Solution for 3(y-4)=6y+6 equation: 



3(y-4)=6y+6

We move all terms to the left:

3(y-4)-(6y+6)=0

We multiply parentheses

3y-(6y+6)-12=0

We get rid of parentheses

3y-6y-6-12=0

We add all the numbers together, and all the variables

-3y-18=0

We move all terms containing y to the left, all other terms to the right

-3y=18

y=18/-3

y=-6

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