3(y-4)=6y-33

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Solution for 3(y-4)=6y-33 equation: 



3(y-4)=6y-33

We move all terms to the left:

3(y-4)-(6y-33)=0

We multiply parentheses

3y-(6y-33)-12=0

We get rid of parentheses

3y-6y+33-12=0

We add all the numbers together, and all the variables

-3y+21=0

We move all terms containing y to the left, all other terms to the right

-3y=-21

y=-21/-3

y=+7

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