3(y-5)+10=16

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Solution for 3(y-5)+10=16 equation: 



3(y-5)+10=16

We move all terms to the left:

3(y-5)+10-(16)=0

We add all the numbers together, and all the variables

3(y-5)-6=0

We multiply parentheses

3y-15-6=0

We add all the numbers together, and all the variables

3y-21=0

We move all terms containing y to the left, all other terms to the right

3y=21

y=21/3

y=7

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