3(y-5)+2(y+3)=16

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Solution for 3(y-5)+2(y+3)=16 equation:


Simplifying
3(y + -5) + 2(y + 3) = 16

Reorder the terms:
3(-5 + y) + 2(y + 3) = 16
(-5 * 3 + y * 3) + 2(y + 3) = 16
(-15 + 3y) + 2(y + 3) = 16

Reorder the terms:
-15 + 3y + 2(3 + y) = 16
-15 + 3y + (3 * 2 + y * 2) = 16
-15 + 3y + (6 + 2y) = 16

Reorder the terms:
-15 + 6 + 3y + 2y = 16

Combine like terms: -15 + 6 = -9
-9 + 3y + 2y = 16

Combine like terms: 3y + 2y = 5y
-9 + 5y = 16

Solving
-9 + 5y = 16

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '9' to each side of the equation.
-9 + 9 + 5y = 16 + 9

Combine like terms: -9 + 9 = 0
0 + 5y = 16 + 9
5y = 16 + 9

Combine like terms: 16 + 9 = 25
5y = 25

Divide each side by '5'.
y = 5

Simplifying
y = 5

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