3(y-5)+2(y+4)=28

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Solution for 3(y-5)+2(y+4)=28 equation: 


Simplifying
3(y + -5) + 2(y + 4) = 28

Reorder the terms:
3(-5 + y) + 2(y + 4) = 28
(-5 * 3 + y * 3) + 2(y + 4) = 28
(-15 + 3y) + 2(y + 4) = 28

Reorder the terms:
-15 + 3y + 2(4 + y) = 28
-15 + 3y + (4 * 2 + y * 2) = 28
-15 + 3y + (8 + 2y) = 28

Reorder the terms:
-15 + 8 + 3y + 2y = 28

Combine like terms: -15 + 8 = -7
-7 + 3y + 2y = 28

Combine like terms: 3y + 2y = 5y
-7 + 5y = 28

Solving
-7 + 5y = 28

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '7' to each side of the equation.
-7 + 7 + 5y = 28 + 7

Combine like terms: -7 + 7 = 0
0 + 5y = 28 + 7
5y = 28 + 7

Combine like terms: 28 + 7 = 35
5y = 35

Divide each side by '5'.
y = 7

Simplifying
y = 7

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