3(y-5)+2=15

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Solution for 3(y-5)+2=15 equation: 



3(y-5)+2=15

We move all terms to the left:

3(y-5)+2-(15)=0

We add all the numbers together, and all the variables

3(y-5)-13=0

We multiply parentheses

3y-15-13=0

We add all the numbers together, and all the variables

3y-28=0

We move all terms containing y to the left, all other terms to the right

3y=28

y=28/3

y=9+1/3

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