3(y-5)+4(10-2y)=0

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Solution for 3(y-5)+4(10-2y)=0 equation: 



3(y-5)+4(10-2y)=0

We add all the numbers together, and all the variables

3(y-5)+4(-2y+10)=0

We multiply parentheses

3y-8y-15+40=0

We add all the numbers together, and all the variables

-5y+25=0

We move all terms containing y to the left, all other terms to the right

-5y=-25

y=-25/-5

y=+5

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