3(y-5)-8=-3(-7+3)-8y

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Solution for 3(y-5)-8=-3(-7+3)-8y equation: 



3(y-5)-8=-3(-7+3)-8y

We move all terms to the left:

3(y-5)-8-(-3(-7+3)-8y)=0

We add all the numbers together, and all the variables

3(y-5)-(-3(-4)-8y)-8=0

We multiply parentheses

3y-(-3(-4)-8y)-15-8=0



We calculate terms in parentheses: -(-3(-4)-8y), so:

-3(-4)-8y

determiningTheFunctionDomain
-8y-3(-4)

We add all the numbers together, and all the variables

-8y+12

Back to the equation:

-(-8y+12)



We add all the numbers together, and all the variables

3y-(-8y+12)-23=0

We get rid of parentheses

3y+8y-12-23=0

We add all the numbers together, and all the variables

11y-35=0

We move all terms containing y to the left, all other terms to the right

11y=35

y=35/11

y=3+2/11

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