3(y-5)-8=-3(y-3)

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Solution for 3(y-5)-8=-3(y-3) equation: 



3(y-5)-8=-3(y-3)

We move all terms to the left:

3(y-5)-8-(-3(y-3))=0

We multiply parentheses

3y-(-3(y-3))-15-8=0



We calculate terms in parentheses: -(-3(y-3)), so:

-3(y-3)

We multiply parentheses

-3y+9

Back to the equation:

-(-3y+9)



We add all the numbers together, and all the variables

3y-(-3y+9)-23=0

We get rid of parentheses

3y+3y-9-23=0

We add all the numbers together, and all the variables

6y-32=0

We move all terms containing y to the left, all other terms to the right

6y=32

y=32/6

y=5+1/3

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