3(y-5)-8=-5(4y+7)-7y

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Solution for 3(y-5)-8=-5(4y+7)-7y equation: 



3(y-5)-8=-5(4y+7)-7y

We move all terms to the left:

3(y-5)-8-(-5(4y+7)-7y)=0

We multiply parentheses

3y-(-5(4y+7)-7y)-15-8=0



We calculate terms in parentheses: -(-5(4y+7)-7y), so:

-5(4y+7)-7y

We add all the numbers together, and all the variables

-7y-5(4y+7)

We multiply parentheses

-7y-20y-35

We add all the numbers together, and all the variables

-27y-35

Back to the equation:

-(-27y-35)



We add all the numbers together, and all the variables

3y-(-27y-35)-23=0

We get rid of parentheses

3y+27y+35-23=0

We add all the numbers together, and all the variables

30y+12=0

We move all terms containing y to the left, all other terms to the right

30y=-12

y=-12/30

y=-2/5

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