3(y-5)=-4y+13

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Solution for 3(y-5)=-4y+13 equation: 



3(y-5)=-4y+13

We move all terms to the left:

3(y-5)-(-4y+13)=0

We multiply parentheses

3y-(-4y+13)-15=0

We get rid of parentheses

3y+4y-13-15=0

We add all the numbers together, and all the variables

7y-28=0

We move all terms containing y to the left, all other terms to the right

7y=28

y=28/7

y=4

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