3(y-5)=2(2y-3)

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Solution for 3(y-5)=2(2y-3) equation:



3(y-5)=2(2y-3)
We move all terms to the left:
3(y-5)-(2(2y-3))=0
We multiply parentheses
3y-(2(2y-3))-15=0
We calculate terms in parentheses: -(2(2y-3)), so:
2(2y-3)
We multiply parentheses
4y-6
Back to the equation:
-(4y-6)
We get rid of parentheses
3y-4y+6-15=0
We add all the numbers together, and all the variables
-1y-9=0
We move all terms containing y to the left, all other terms to the right
-y=9
y=9/-1
y=-9

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