3(y-5)=4(y-1)

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Solution for 3(y-5)=4(y-1) equation: 



3(y-5)=4(y-1)

We move all terms to the left:

3(y-5)-(4(y-1))=0

We multiply parentheses

3y-(4(y-1))-15=0



We calculate terms in parentheses: -(4(y-1)), so:

4(y-1)

We multiply parentheses

4y-4

Back to the equation:

-(4y-4)



We get rid of parentheses

3y-4y+4-15=0

We add all the numbers together, and all the variables

-1y-11=0

We move all terms containing y to the left, all other terms to the right

-y=11

y=11/-1

y=-11

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