3(y-5)=7y+10

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Solution for 3(y-5)=7y+10 equation: 



3(y-5)=7y+10

We move all terms to the left:

3(y-5)-(7y+10)=0

We multiply parentheses

3y-(7y+10)-15=0

We get rid of parentheses

3y-7y-10-15=0

We add all the numbers together, and all the variables

-4y-25=0

We move all terms containing y to the left, all other terms to the right

-4y=25

y=25/-4

y=-6+1/4

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