3(y-5)=y-4+3y

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Solution for 3(y-5)=y-4+3y equation: 



3(y-5)=y-4+3y

We move all terms to the left:

3(y-5)-(y-4+3y)=0

We add all the numbers together, and all the variables

3(y-5)-(4y-4)=0

We multiply parentheses

3y-(4y-4)-15=0

We get rid of parentheses

3y-4y+4-15=0

We add all the numbers together, and all the variables

-1y-11=0

We move all terms containing y to the left, all other terms to the right

-y=11

y=11/-1

y=-11

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