3(y-6)=-2(2y+2)

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Solution for 3(y-6)=-2(2y+2) equation: 



3(y-6)=-2(2y+2)

We move all terms to the left:

3(y-6)-(-2(2y+2))=0

We multiply parentheses

3y-(-2(2y+2))-18=0



We calculate terms in parentheses: -(-2(2y+2)), so:

-2(2y+2)

We multiply parentheses

-4y-4

Back to the equation:

-(-4y-4)



We get rid of parentheses

3y+4y+4-18=0

We add all the numbers together, and all the variables

7y-14=0

We move all terms containing y to the left, all other terms to the right

7y=14

y=14/7

y=2

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