3(y-6)=3(y-4)-y

Solution for 3(y-6)=3(y-4)-y equation:

3(y-6)=3(y-4)-y

We move all terms to the left:

3(y-6)-(3(y-4)-y)=0

We multiply parentheses

3y-(3(y-4)-y)-18=0


We calculate terms in parentheses: -(3(y-4)-y), so:

3(y-4)-y

We add all the numbers together, and all the variables

-1y+3(y-4)

We multiply parentheses

-1y+3y-12

We add all the numbers together, and all the variables

2y-12

Back to the equation:

-(2y-12)


We get rid of parentheses

3y-2y+12-18=0

We add all the numbers together, and all the variables

y-6=0

We move all terms containing y to the left, all other terms to the right

y=6