3(y-6)=8y-38

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Solution for 3(y-6)=8y-38 equation:



3(y-6)=8y-38
We move all terms to the left:
3(y-6)-(8y-38)=0
We multiply parentheses
3y-(8y-38)-18=0
We get rid of parentheses
3y-8y+38-18=0
We add all the numbers together, and all the variables
-5y+20=0
We move all terms containing y to the left, all other terms to the right
-5y=-20
y=-20/-5
y=+4

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