3(y-7)+16=2(-4+y)+y-1

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Solution for 3(y-7)+16=2(-4+y)+y-1 equation: 



3(y-7)+16=2(-4+y)+y-1

We move all terms to the left:

3(y-7)+16-(2(-4+y)+y-1)=0

We add all the numbers together, and all the variables

3(y-7)-(2(y-4)+y-1)+16=0

We multiply parentheses

3y-(2(y-4)+y-1)-21+16=0



We calculate terms in parentheses: -(2(y-4)+y-1), so:

2(y-4)+y-1

We add all the numbers together, and all the variables

y+2(y-4)-1

We multiply parentheses

y+2y-8-1

We add all the numbers together, and all the variables

3y-9

Back to the equation:

-(3y-9)



We add all the numbers together, and all the variables

3y-(3y-9)-5=0

We get rid of parentheses

3y-3y+9-5=0

We add all the numbers together, and all the variables

4!=0

There is no solution for this equation

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