3(y-7)+7y=-31

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Solution for 3(y-7)+7y=-31 equation: 



3(y-7)+7y=-31

We move all terms to the left:

3(y-7)+7y-(-31)=0

We add all the numbers together, and all the variables

7y+3(y-7)+31=0

We multiply parentheses

7y+3y-21+31=0

We add all the numbers together, and all the variables

10y+10=0

We move all terms containing y to the left, all other terms to the right

10y=-10

y=-10/10

y=-1

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