3(y-7)-16=2(5y+1)-4

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Solution for 3(y-7)-16=2(5y+1)-4 equation: 



3(y-7)-16=2(5y+1)-4

We move all terms to the left:

3(y-7)-16-(2(5y+1)-4)=0

We multiply parentheses

3y-(2(5y+1)-4)-21-16=0



We calculate terms in parentheses: -(2(5y+1)-4), so:

2(5y+1)-4

We multiply parentheses

10y+2-4

We add all the numbers together, and all the variables

10y-2

Back to the equation:

-(10y-2)



We add all the numbers together, and all the variables

3y-(10y-2)-37=0

We get rid of parentheses

3y-10y+2-37=0

We add all the numbers together, and all the variables

-7y-35=0

We move all terms containing y to the left, all other terms to the right

-7y=35

y=35/-7

y=-5

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