3(y-7)-2(-y-4)=-4(-y-2)+y-2

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Solution for 3(y-7)-2(-y-4)=-4(-y-2)+y-2 equation:



3(y-7)-2(-y-4)=-4(-y-2)+y-2
We move all terms to the left:
3(y-7)-2(-y-4)-(-4(-y-2)+y-2)=0
We add all the numbers together, and all the variables
3(y-7)-2(-1y-4)-(-4(-1y-2)+y-2)=0
We multiply parentheses
3y+2y-(-4(-1y-2)+y-2)-21+8=0
We calculate terms in parentheses: -(-4(-1y-2)+y-2), so:
-4(-1y-2)+y-2
We add all the numbers together, and all the variables
y-4(-1y-2)-2
We multiply parentheses
y+4y+8-2
We add all the numbers together, and all the variables
5y+6
Back to the equation:
-(5y+6)
We add all the numbers together, and all the variables
5y-(5y+6)-13=0
We get rid of parentheses
5y-5y-6-13=0
We add all the numbers together, and all the variables
-19!=0
There is no solution for this equation

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