3(y-7)-2(-y-4)=-4(-y-2)+y-2

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Solution for 3(y-7)-2(-y-4)=-4(-y-2)+y-2 equation: 



3(y-7)-2(-y-4)=-4(-y-2)+y-2

We move all terms to the left:

3(y-7)-2(-y-4)-(-4(-y-2)+y-2)=0

We add all the numbers together, and all the variables

3(y-7)-2(-1y-4)-(-4(-1y-2)+y-2)=0

We multiply parentheses

3y+2y-(-4(-1y-2)+y-2)-21+8=0



We calculate terms in parentheses: -(-4(-1y-2)+y-2), so:

-4(-1y-2)+y-2

We add all the numbers together, and all the variables

y-4(-1y-2)-2

We multiply parentheses

y+4y+8-2

We add all the numbers together, and all the variables

5y+6

Back to the equation:

-(5y+6)



We add all the numbers together, and all the variables

5y-(5y+6)-13=0

We get rid of parentheses

5y-5y-6-13=0

We add all the numbers together, and all the variables

-19!=0

There is no solution for this equation

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