3(y-7)-5(y+2)=2y+4+3y

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Solution for 3(y-7)-5(y+2)=2y+4+3y equation: 



3(y-7)-5(y+2)=2y+4+3y

We move all terms to the left:

3(y-7)-5(y+2)-(2y+4+3y)=0

We add all the numbers together, and all the variables

3(y-7)-5(y+2)-(5y+4)=0

We multiply parentheses

3y-5y-(5y+4)-21-10=0

We get rid of parentheses

3y-5y-5y-4-21-10=0

We add all the numbers together, and all the variables

-7y-35=0

We move all terms containing y to the left, all other terms to the right

-7y=35

y=35/-7

y=-5

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