3(y-7)-5=-3(-8+4)-3y

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Solution for 3(y-7)-5=-3(-8+4)-3y equation: 



3(y-7)-5=-3(-8+4)-3y

We move all terms to the left:

3(y-7)-5-(-3(-8+4)-3y)=0

We add all the numbers together, and all the variables

3(y-7)-(-3(-4)-3y)-5=0

We multiply parentheses

3y-(-3(-4)-3y)-21-5=0



We calculate terms in parentheses: -(-3(-4)-3y), so:

-3(-4)-3y

determiningTheFunctionDomain
-3y-3(-4)

We add all the numbers together, and all the variables

-3y+12

Back to the equation:

-(-3y+12)



We add all the numbers together, and all the variables

3y-(-3y+12)-26=0

We get rid of parentheses

3y+3y-12-26=0

We add all the numbers together, and all the variables

6y-38=0

We move all terms containing y to the left, all other terms to the right

6y=38

y=38/6

y=6+1/3

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