3(y-7)-8y=19

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Solution for 3(y-7)-8y=19 equation:



3(y-7)-8y=19
We move all terms to the left:
3(y-7)-8y-(19)=0
We add all the numbers together, and all the variables
-8y+3(y-7)-19=0
We multiply parentheses
-8y+3y-21-19=0
We add all the numbers together, and all the variables
-5y-40=0
We move all terms containing y to the left, all other terms to the right
-5y=40
y=40/-5
y=-8

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