3(y-7)-8y=19

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Solution for 3(y-7)-8y=19 equation: 



3(y-7)-8y=19

We move all terms to the left:

3(y-7)-8y-(19)=0

We add all the numbers together, and all the variables

-8y+3(y-7)-19=0

We multiply parentheses

-8y+3y-21-19=0

We add all the numbers together, and all the variables

-5y-40=0

We move all terms containing y to the left, all other terms to the right

-5y=40

y=40/-5

y=-8

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