3(y-7)-9=-3(-9y+6)-8y

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Solution for 3(y-7)-9=-3(-9y+6)-8y equation: 



3(y-7)-9=-3(-9y+6)-8y

We move all terms to the left:

3(y-7)-9-(-3(-9y+6)-8y)=0

We multiply parentheses

3y-(-3(-9y+6)-8y)-21-9=0



We calculate terms in parentheses: -(-3(-9y+6)-8y), so:

-3(-9y+6)-8y

We add all the numbers together, and all the variables

-8y-3(-9y+6)

We multiply parentheses

-8y+27y-18

We add all the numbers together, and all the variables

19y-18

Back to the equation:

-(19y-18)



We add all the numbers together, and all the variables

3y-(19y-18)-30=0

We get rid of parentheses

3y-19y+18-30=0

We add all the numbers together, and all the variables

-16y-12=0

We move all terms containing y to the left, all other terms to the right

-16y=12

y=12/-16

y=-3/4

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