3(y-7)=-3y+27

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Solution for 3(y-7)=-3y+27 equation: 



3(y-7)=-3y+27

We move all terms to the left:

3(y-7)-(-3y+27)=0

We multiply parentheses

3y-(-3y+27)-21=0

We get rid of parentheses

3y+3y-27-21=0

We add all the numbers together, and all the variables

6y-48=0

We move all terms containing y to the left, all other terms to the right

6y=48

y=48/6

y=8

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