3(y-7)=-6(y+2)

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Solution for 3(y-7)=-6(y+2) equation: 



3(y-7)=-6(y+2)

We move all terms to the left:

3(y-7)-(-6(y+2))=0

We multiply parentheses

3y-(-6(y+2))-21=0



We calculate terms in parentheses: -(-6(y+2)), so:

-6(y+2)

We multiply parentheses

-6y-12

Back to the equation:

-(-6y-12)



We get rid of parentheses

3y+6y+12-21=0

We add all the numbers together, and all the variables

9y-9=0

We move all terms containing y to the left, all other terms to the right

9y=9

y=9/9

y=1

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