3(y-7)=6(y+2)

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Solution for 3(y-7)=6(y+2) equation: 



3(y-7)=6(y+2)

We move all terms to the left:

3(y-7)-(6(y+2))=0

We multiply parentheses

3y-(6(y+2))-21=0



We calculate terms in parentheses: -(6(y+2)), so:

6(y+2)

We multiply parentheses

6y+12

Back to the equation:

-(6y+12)



We get rid of parentheses

3y-6y-12-21=0

We add all the numbers together, and all the variables

-3y-33=0

We move all terms containing y to the left, all other terms to the right

-3y=33

y=33/-3

y=-11

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