3(y-8)+7=5(y+2)-2y-27

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Solution for 3(y-8)+7=5(y+2)-2y-27 equation: 



3(y-8)+7=5(y+2)-2y-27

We move all terms to the left:

3(y-8)+7-(5(y+2)-2y-27)=0

We multiply parentheses

3y-(5(y+2)-2y-27)-24+7=0



We calculate terms in parentheses: -(5(y+2)-2y-27), so:

5(y+2)-2y-27

We add all the numbers together, and all the variables

-2y+5(y+2)-27

We multiply parentheses

-2y+5y+10-27

We add all the numbers together, and all the variables

3y-17

Back to the equation:

-(3y-17)



We add all the numbers together, and all the variables

3y-(3y-17)-17=0

We get rid of parentheses

3y-3y+17-17=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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