3(y-9)-1=-5(-4y+2)-5y

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Solution for 3(y-9)-1=-5(-4y+2)-5y equation: 



3(y-9)-1=-5(-4y+2)-5y

We move all terms to the left:

3(y-9)-1-(-5(-4y+2)-5y)=0

We multiply parentheses

3y-(-5(-4y+2)-5y)-27-1=0



We calculate terms in parentheses: -(-5(-4y+2)-5y), so:

-5(-4y+2)-5y

We add all the numbers together, and all the variables

-5y-5(-4y+2)

We multiply parentheses

-5y+20y-10

We add all the numbers together, and all the variables

15y-10

Back to the equation:

-(15y-10)



We add all the numbers together, and all the variables

3y-(15y-10)-28=0

We get rid of parentheses

3y-15y+10-28=0

We add all the numbers together, and all the variables

-12y-18=0

We move all terms containing y to the left, all other terms to the right

-12y=18

y=18/-12

y=-1+1/2

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