3(y-9)-4=-3(-6y+9)-y

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Solution for 3(y-9)-4=-3(-6y+9)-y equation: 



3(y-9)-4=-3(-6y+9)-y

We move all terms to the left:

3(y-9)-4-(-3(-6y+9)-y)=0

We multiply parentheses

3y-(-3(-6y+9)-y)-27-4=0



We calculate terms in parentheses: -(-3(-6y+9)-y), so:

-3(-6y+9)-y

We add all the numbers together, and all the variables

-1y-3(-6y+9)

We multiply parentheses

-1y+18y-27

We add all the numbers together, and all the variables

17y-27

Back to the equation:

-(17y-27)



We add all the numbers together, and all the variables

3y-(17y-27)-31=0

We get rid of parentheses

3y-17y+27-31=0

We add all the numbers together, and all the variables

-14y-4=0

We move all terms containing y to the left, all other terms to the right

-14y=4

y=4/-14

y=-2/7

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