3(y-9)=12y+13

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Solution for 3(y-9)=12y+13 equation: 



3(y-9)=12y+13

We move all terms to the left:

3(y-9)-(12y+13)=0

We multiply parentheses

3y-(12y+13)-27=0

We get rid of parentheses

3y-12y-13-27=0

We add all the numbers together, and all the variables

-9y-40=0

We move all terms containing y to the left, all other terms to the right

-9y=40

y=40/-9

y=-4+4/9

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