3(y-9)=9y+15

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Solution for 3(y-9)=9y+15 equation: 



3(y-9)=9y+15

We move all terms to the left:

3(y-9)-(9y+15)=0

We multiply parentheses

3y-(9y+15)-27=0

We get rid of parentheses

3y-9y-15-27=0

We add all the numbers together, and all the variables

-6y-42=0

We move all terms containing y to the left, all other terms to the right

-6y=42

y=42/-6

y=-7

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