3(y=1)=4=2(y-1)+y+y

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Solution for 3(y=1)=4=2(y-1)+y+y equation: 



3(y=1)=4=2(y-1)+y+y

We move all terms to the left:

3(y-(1))=0

We multiply parentheses

3y-3=0

We move all terms containing y to the left, all other terms to the right

3y=3

y=3/3

y=1

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