3(y=1)=4=2(y-1)+y+y

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Solution for 3(y=1)=4=2(y-1)+y+y equation:



3(y=1)=4=2(y-1)+y+y
We move all terms to the left:
3(y-(1))=0
We multiply parentheses
3y-3=0
We move all terms containing y to the left, all other terms to the right
3y=3
y=3/3
y=1

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