3(z+-4)=-6

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Solution for 3(z+-4)=-6 equation:



3(z+-4)=-6
We move all terms to the left:
3(z+-4)-(-6)=0
We add all the numbers together, and all the variables
3(z-4)-(-6)=0
We add all the numbers together, and all the variables
3(z-4)+6=0
We multiply parentheses
3z-12+6=0
We add all the numbers together, and all the variables
3z-6=0
We move all terms containing z to the left, all other terms to the right
3z=6
z=6/3
z=2

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