3(z+-4)=-6

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Solution for 3(z+-4)=-6 equation: 



3(z+-4)=-6

We move all terms to the left:

3(z+-4)-(-6)=0

We add all the numbers together, and all the variables

3(z-4)-(-6)=0

We add all the numbers together, and all the variables

3(z-4)+6=0

We multiply parentheses

3z-12+6=0

We add all the numbers together, and all the variables

3z-6=0

We move all terms containing z to the left, all other terms to the right

3z=6

z=6/3

z=2

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