3(z+1)+11=-2(z+13)

Solution for 3(z+1)+11=-2(z+13) equation:

Simplifying
3(z + 1) + 11 = -2(z + 13)

Reorder the terms:
3(1 + z) + 11 = -2(z + 13)
(1 * 3 + z * 3) + 11 = -2(z + 13)
(3 + 3z) + 11 = -2(z + 13)

Reorder the terms:
3 + 11 + 3z = -2(z + 13)

Combine like terms: 3 + 11 = 14
14 + 3z = -2(z + 13)

Reorder the terms:
14 + 3z = -2(13 + z)
14 + 3z = (13 * -2 + z * -2)
14 + 3z = (-26 + -2z)

Solving
14 + 3z = -26 + -2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '2z' to each side of the equation.
14 + 3z + 2z = -26 + -2z + 2z

Combine like terms: 3z + 2z = 5z
14 + 5z = -26 + -2z + 2z

Combine like terms: -2z + 2z = 0
14 + 5z = -26 + 0
14 + 5z = -26

Add '-14' to each side of the equation.
14 + -14 + 5z = -26 + -14

Combine like terms: 14 + -14 = 0
0 + 5z = -26 + -14
5z = -26 + -14

Combine like terms: -26 + -14 = -40
5z = -40

Divide each side by '5'.
z = -8

Simplifying
z = -8