3(z+1)+11=-2z-28

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Solution for 3(z+1)+11=-2z-28 equation: 



3(z+1)+11=-2z-28

We move all terms to the left:

3(z+1)+11-(-2z-28)=0

We multiply parentheses

3z-(-2z-28)+3+11=0

We get rid of parentheses

3z+2z+28+3+11=0

We add all the numbers together, and all the variables

5z+42=0

We move all terms containing z to the left, all other terms to the right

5z=-42

z=-42/5

z=-8+2/5

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