3(z+1)+2(z-1)=6

Solution for 3(z+1)+2(z-1)=6 equation:

Simplifying
3(z + 1) + 2(z + -1) = 6

Reorder the terms:
3(1 + z) + 2(z + -1) = 6
(1 * 3 + z * 3) + 2(z + -1) = 6
(3 + 3z) + 2(z + -1) = 6

Reorder the terms:
3 + 3z + 2(-1 + z) = 6
3 + 3z + (-1 * 2 + z * 2) = 6
3 + 3z + (-2 + 2z) = 6

Reorder the terms:
3 + -2 + 3z + 2z = 6

Combine like terms: 3 + -2 = 1
1 + 3z + 2z = 6

Combine like terms: 3z + 2z = 5z
1 + 5z = 6

Solving
1 + 5z = 6

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 5z = 6 + -1

Combine like terms: 1 + -1 = 0
0 + 5z = 6 + -1
5z = 6 + -1

Combine like terms: 6 + -1 = 5
5z = 5

Divide each side by '5'.
z = 1

Simplifying
z = 1